subtract and reduce in lowest terms 3all over x squared minus 4 all over 4x squared minis 16x?

Answer 1

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[3/(x^2-4)] / (4x^2-16x) , is that right?

Answer 2

(x^2 - 4) = (x+2)(x-2) (x - 12) can't be factored Rewriting the denominator as (36 - x^2) = -(x^2 - 36) = -(x+6)(x-6) The fraction will become [(x+2)(x-2)(x-12)]/[-(x+6)(x-6)] No cancellation is available