A tank of gas is at 0 degress celcius. It contains 4 moles of gas: 1 mole of oxygen, and 3 moles of Neon. The volume of the tank is 11.2 L. What is the partial pressure of oxygen in the tank?
2006-11-27 03:58:33 · 8 answers · asked by rnjes21 2 in Science & Mathematics ➔ Chemistry
Partial pressure of oxygen is the mole fraction of oxygen times the total pressure. Mole fraction is computed as follows:
Mole Frac (O2) = 1 Mole O2 / 4 Moles of gas =1/4
2006-11-27 04:07:51 · answer #1 · answered by Anonymous · 0⤊ 1⤋
If the oxygen alone occupied the volume, neglecting the neon, that is the partial pressure of the oxygen.
The volume is 11.2 L
The STP (standard temperature and pressure law) states that one mole of a gas will occupy 22.4 L @
O degrees C @ 1 atm pressure.
Here, one mole occupies 11.2 L @ 0 C so the pressure (partial pressure) is 2 atm.
2006-11-27 04:24:25 · answer #2 · answered by Anonymous · 0⤊ 1⤋
Partial pressure of oxygen in the tank IS 2 atm.
xi = ni / n,where
xi = mole fraction of any individual gas component in a gas mixture
Pi = partial pressure of any individual gas component in a gas mixture
ni = moles of any individual gas component in a gas mixture
n = total moles of the gas mixture
xi =1/4
xi =0.25(mole fraction Of oxygen)
Pi =xi *P
P= total pressure of the gas mixture
USE ,
P*V=n*R*T
FIND OUT THE VALUE OF P AND Pi .
PV = nRT
V = 11.2L
n = 1
R = 0.082
T = 0 + 273
P = 1x0.082x273/11.2
P = 2.0 atm
2006-11-27 04:33:16 · answer #3 · answered by Anonymous · 0⤊ 0⤋
the partial pressure of the Oxygen is 1/4 of the total pressure of the combined gas.
2006-11-27 04:02:18 · answer #4 · answered by DanE 7 · 0⤊ 1⤋
i desire you comprehend you ought to remodel 21 C to Kelvin it rather is 294 ok and 35 C to 304 ok now , plug into formula: (left area is for the previous length and good area is for the after measuremnts. do not mess those up!!!) PV/T=PV/T (50*25)/294=(P*40 5)/304 (confirm for P on the right, the stress after heating) (50*25*304)/(294*40 5)=P 28.seventy 2=P 28.seventy 2 atm is the hot stress
2016-11-27 01:40:59 · answer #5 · answered by faccone 4 · 0⤊ 0⤋
PV = nRT
V = 11.2L
n = 1
R = 0.082
T = 0 + 273
P = 1x0.082x273/11.2
P = 2.0 atm
2006-11-27 04:02:46 · answer #6 · answered by Jabberwock 5 · 0⤊ 1⤋
Too hard for a Monday morning, sorry!
2006-11-27 03:59:35 · answer #7 · answered by ndtaya 6 · 0⤊ 1⤋
just looking around
2006-11-27 04:00:14 · answer #8 · answered by nick s 2 · 0⤊ 1⤋