Is the math statement true or false?

Question

Problem 1:
-8 < -(sq root)40 < -7
TRUE OR FALSE?

Problem 2:
9 < 3(sq root)51 < 10
TRUE OR FALSE?

Answer 1

- 8 < √40 < - 7

-8 < √4 √10 < - 7

-8 < 2 √10 < - 7

-8 < 2 x 3.16227766 < - 7

- 8 < 6.32455532 < - 7

This above statement is FALSE

- - - - - - - - - - - - - - - - - - - - -

9 < √ 51 < 10

9 < √1 √50 < 10

9 < √1 √2 √25 < 10

9 < 1 x 1,414213562 x 5 < 10

9 < 7.071067812 < 10

The above statement is FALSE

- - - - - -S-

Answer 2

Of course, it's false. Because when -8 < -(sq root)40 < -7 is squared we got 64 > 40 > 49 which is also false. Now therefore, the above statement of yours is false.
2nd reason, the negative square root of 40 is greater than -7.

Problem 2.
9 < 3(sq root)51 < 10 will become 9 < 21.4242852 < 10 which is also a false.

Answer 3

the square root of 40 is between 6 (36) and 7 (49)... so the first problem is false because it would be > -7 also.

The square root of 51 is between 7 (49) and 8 (64)... so the second problem is also false because 3*sqroot 51 would be between 21 and 24... which is >10.

Answer 4

the exterior are and volume of a sphere do substitute at different expenses, on situation that SA=4pi(r)^2 and V=4/3pi(r)^3. even with the obtrusive undeniable actuality that, through way of actuality the purely non-consistent variable interior both equations is r, the radius has to get smaller for both to shrink, and both ought to ought to if the radius is getting smaller. So pretend.

Answer 5

Don't know, don't care, I passed math when i was in school the old fashioned way. I copied off my nerdy friend!

Answer 6

i'm not sure that these are set up as usable equations-