2x - 5x^1/2 - 3 = 0
2006-11-27 03:31:28 · 3 answers · asked by sillyboys_trucksare4girls 2 in Science & Mathematics ➔ Mathematics
2x - 5x^1/2 - 3 = 0
2x-3= 5x^1/2
square both sides:
(2x-3)^2 = 25x
4x^2 - 12x + 9 = 25x
4x^2 -37x +9 =0
x= ( 37 +- sqrt( 37^2 -4(4)(9) ) /2(4)
x= ( 37 +- sqrt( 1225 ) /2(4)
x= ( 37 +- 35 )/2(4)
x= 72/8 or x= 2/8
x= 9 or x = 1/4
2006-11-27 03:34:17 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Factor this into
(2x^(1/2) +1)(x^(1/2) - 3)=0
2x(1/2)=-1
x(1/2)=-1/2
x=1/4
Also x^(1/2)=3
x=9
Check with 1/4
2/4 + 5/2 - 3= 0 Use (1/4)^1/2= -1/2
Check with 9
18 -5(3) -3 = 0 Use 9^(1/2)=+3
2006-11-27 11:42:22 · answer #2 · answered by albert 5 · 0⤊ 1⤋
(2âx + 1)(âx - 3) = 0
x = ¼i, 9
So, the only real solution would be 9.
2006-11-27 11:36:34 · answer #3 · answered by Dave 6 · 0⤊ 1⤋