2006-11-27 03:26:03 · 4 answers · asked by taylor_boswell 1 in Science & Mathematics ➔ Mathematics
log a (7x+1)=log a (4x+16)
7x+1= 4x+16
3x = 15
x= 5
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2006-11-27 03:29:58 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Is there supposed to be an exponent sign after each "log a"? If so, the answer is
log(a)^x = x*log(a)
So, the next step for your solution is:
(7x + 1) * log(a) = (4x + 16) * log(a)
Now divide both sides by log(a) and solve for x.
2006-11-27 03:29:29 · answer #2 · answered by Dave 6 · 0⤊ 0⤋
because logs are same
so 7x+1 = 4x+16
take 1 to RHS and 4x to LHS
7x-4x = 16-1
3x = 15
x = 5
2006-11-27 03:29:23 · answer #3 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
here the two terms are equal.
hence by taking the antilog of both terms we get
7x+1=4x+16
7x-4x=16-1
3x=15
x=15/3
x=5
2006-11-27 03:31:19 · answer #4 · answered by DOOM 2 · 0⤊ 0⤋