Find the distance between the points A(4,-3) and B(-4,3)?

Answer 1

The distance between two points is defined by the following equation derived from the pythagorean theorum:

d = sqrt((x2 - x1)^2 + (y2-y1)^2)

Where (x1, y1) is the coordinates of the first point and (x2, y2) is the coordinates of the second point.

For your problem,

(x1, y1) = (4, -3)
(x2, y2) = (-4, 3)

d = sqrt((-4 - 4)^2 + (3 - -3)^2)
d = sqrt((-8)^2 + (6)^2)
d = sqrt(64 + 36)
d = sqrt(100)
d = 10

The distance between the two points is 10.

I hope this helps!

Answer 2

AB^2=(3+3)^2+(-4-4)^2
=36+64
=100
AB=10

Answer 3

The line passing through these points passes through origin.The distance between these points can be calculated by the Pythagoras Theorem.
Point A lies in the fourth quadrant.Its X coordinate is 4 & its distance from Y-axis is 4 units & Y coordinate is -3 but its distance from X axis is 3 units (as distance is never negative).Hence by the theorem,distance of A is 5 units.
The same procedure can be used to find the distance of point B from origin condition is its X & Y coordinates are changed.
The distance of point B from the origin is also 5 units.
Hence the distance between points A(4,-3) & B(-4,3) is
5+5=10 units
Its easy to solve such types of questions if you know the Pythagoras theorem.

Answer 4

Think of this as a right-angled triangle, and you are trying to find the hypotenuse. Use the Pythagorean theorem. The difference in the x-coordinates is 8, in the y-coordinates it is 6. 8^2 + 6^2 = 64 + 36 = 100. Take the square root of 100, and the answer is 10.

Answer 5

At a glance, I would say 10.
subtract the x's.... 8
subtract th y's ....6
It's a classic 3,4,5 right triangle.....6,8.10

Answer 6

d=sqrt((-4-4)^2 + (-3-3)^2)
good luck