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What is the acceleration of a .4 kg ball from rest to 9 m/s during the .15 s in which her foot is in contact with the ball.

2006-11-27 02:55:55 · 3 answers · asked by this Mike guy 5 in Science & Mathematics Physics

3 answers

mass doesn't matter here, just the acceleration
v=u+at
a=(v-u)/t
a=(9-0)/0.15=60 m/s^2

2006-11-27 03:13:20 · answer #1 · answered by Shug 2 · 0 0

a = (v-u)/t
mass here is irrelevant
v= final velocity
u=initial velocity
therefore
a= (9-0)/.15 m/s^2
=60 m/s^2

2006-11-27 11:09:33 · answer #2 · answered by digitallyneosticated 2 · 0 0

law of physics...

2006-11-27 10:57:31 · answer #3 · answered by Anonymous · 0 1

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