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There is no such thing as the perpendicular bisector of a triangle. You can, however, find the perpendicular bisector of any of the three sides of the triangle.

Suppose you have a triangle called ABC and you wish to find the perpendicular bisector of the side AB. Simply put the point of a compass at point A and open up the compass so that the pencil end is at point B. Then draw a circle. Now put the point of the compass on point B and the pencil end on point A and draw another circle. The two circles will intersect at two points which you might name E and F. Now draw a line through E and F and passing through AB. This line will be the perpendicular bisector of AB.

Every triangle has three altitudes. In the triangle ABC, the line drawn from C perpendicular to the side AB is an altitude, so is the line drawn from B perpedicular to the line AC, and so is the line drawn from A perpendicular to the line BC.

The area of a triangle = 1/2 base times altitude. So if you know the area (A) and the base (b) then altitude = 2A/b.

Hope this gives you the info you were looking for.

2006-11-27 03:14:13 · answer #1 · answered by ironduke8159 7 · 0 0

A perpendicular bisector of a triangle is a straight line passing through the midpoint of a side and being perpendicular to it, i.e. forming a right angle with it. The three perpendicular bisectors meet in a single point, the triangle's circumcenter; this point is the center of the circumcircle, the circle passing through all three vertices.

2006-11-27 02:53:58 · answer #2 · answered by DanE 7 · 0 0

take any side
with slightly more than half the length of the side draw arcs from both the ends on either side of the side
the line through the point of intersection of the arcs will be the perpendicular bisector

2006-11-27 02:52:51 · answer #3 · answered by raj 7 · 0 0

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