Math Problem help?

0 ⤊

a; b and c are 3 numbers proportional to 4; 6 and 9.
We know that 2a+b=42
Calculate a; b and c

2006-11-27 01:48:45 · 3 answers · asked by Anonymous in Education & Reference ➔ Homework Help

3 answers

If a, b and c are proportional, then to solve this you just had to keep multiplying 4, 6,and 9 by the same number, then substituting it into the equation 2a+b til you get 42.
In this case, you multiplied the numbers by 3:
a=12
b=18
c=27

as 2 x 12 + 18 = 42

2006-11-27 01:55:18 · answer #1 · answered by Elle 3 · 0⤊ 0⤋

Well, I got a=12, b=18 and c=27 in about 1 minute.
a=1.5b, c=1.5b and also 2.25a
What's the problem, very simple algebra?

2006-11-27 09:57:09 · answer #2 · answered by Billybean 7 · 0⤊ 0⤋

Solve for B, then substitute.

2006-11-27 09:50:38 · answer #3 · answered by Anonymous · 0⤊ 0⤋