How many grams does 2.4000x10^22 molecules of C10H22 weigh?

Answer 1

Ooh, good question. First of all, let's figure out what a mole of C10H22 weighs. That's 10* the molar mass of C + 22* the molar mass of H = 10*12.01 + 22*1.007 = 142.254 g. That's for 1 mole, or 6.023*10^23 molecules. 2.4000*10^22 molecules weighs (2.4000E22/6.023E23)*142.254 or 5.668 grams.

I hope that helps.