does the angular momentum in respect of a planet revolving in elliptical orbit around the sun conserve?

Answer 1

Yes!
There's net external torque acting on earth is equal to zero you know.(Only if we diminish the chance of sudden appearance of a comet).
We know,
if the net torque acting on a body, be denoted by T & if J denotes its angular momentum, then,
dJ/dt = T
now, since the net torque on earth is 0( or to be more specific constant)
dJ/dt= rate on change of torque wrt time = 0( in either case)
or J = const
Hence, the conclusion.
But it should be borne in minds that change in the net torque on earth is actually not zero( Beacuse of the celestial bodies other than sun, the sudden appearance of comets etc). But the change in torque is negligible & for all practical purposes can be considered to be zero.

Answer 2

This became proved with the help of Newton. Given an merchandise shifting with some speed, and a gravitational stress equivalent to F = GMm/r^2, then there are 3 plausible curved paths the item may shop on with. It relies upon on how instantly the item is shifting. a million) An open route contained in the variety of a hyperbola. It is presented in from infinity and is going decrease back to infinity. it truly is an merchandise shifting above "get away speed". 2) A closed route contained in the variety of an ellipse. 3) A parabola, if the item is in simple terms on the boundary of skill between the closed and open route. Newton confirmed that if the stress is proportional to at least a million/r^2 and the route is closed, this is going to likely be an ellipse. So that's a effect of the very incontrovertible fact that gravity is an "inverse sq." stress.

Answer 3

Conserve what? If you mean conserve angular momentum, then the angular momentum of the Planet/Sun system is conserved, as it must be.

Answer 4

Yes, it does. This is what leads to one of Kepler's laws that says
"The radius vector of the planet' orbit sweeps equal areas in equal times"

Answer 5

yes ,depends whether planet is in aphelion or perihelion.aphelion-planet is farther in its path,perihelion-planet is closer in its path around the sun.keplers 2 nd law states radius vector of a planet sweeps out equal areas in equal amount of time.so at perhelion planets r faster at perihelion,slower at aphelion.