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How do you factor polynomials with four terms, like this.
x^2y^2 - y^2-15x^2 + 15
Where do you start and what do you do?

2006-11-27 01:39:30 · 4 answers · asked by Mayday Britty 3 in Science & Mathematics Mathematics

4 answers

First you group the 'like terms'; in your example, the first two and the last two. Then you see the common factor and pull it out

y^2(x^2-1) - 15 (x^2-1)
Now you see the common term in both and pull that out
(x^2-1) (y^2-15)

thus you have your two factors of the polynomial

2006-11-27 01:44:29 · answer #1 · answered by profchan 1 · 1 0

x^2y^2-y^2-15x^2+15
=y^2(x^2-1)-15(x^2-1)
=(y^2-15)(x^2-1)
=(y^2-15)(x-1)(x+1)

I don't know of any general technique to solve.Just solve a lot of questions.Crack your head over them.More you practice,more it becomes part of your instinct.Things will start happening on their own.Hope you understand.

Allahuakbar
Slave of Allah

2006-11-27 09:47:53 · answer #2 · answered by Slave_of_Allah 1 · 0 0

x^2y^2 - y^2-15x^2 + 15

Y^2(X^2-1)-15(X^2-1)=0
(Y^2-15)(X^2-1)=0
SO Y^2=15
AND X^2=1
X=+1 OR-1
AND Y=SQRT(15)

2006-11-27 09:44:37 · answer #3 · answered by riya s 2 · 1 0

profchan is right, but you can take it a step or two farther if you want.

(x^2-1) (y^2-15) factors into
(x + 1)(x - 1)(y + √15)(y - √15)

2006-11-27 09:46:53 · answer #4 · answered by Jim Burnell 6 · 1 0

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