2006-11-26 22:46:47 · 5 answers · asked by Venkateswaran A 2 in Science & Mathematics ➔ Mathematics
this means
x^3 = -1
or x^3+1 = 0
f(x) = x^3+1
f(-1) = 0
so one root is -1
for the other root by division
(x+1)(x^2-x+1)
x^2-x+1 = 0 => x= (1+/-sqrt(3)i)/2
2006-11-26 22:52:02 · answer #1 · answered by Mein Hoon Na 7 · 1⤊ 0⤋
-1, (1+iâ3)/2, and (1-iâ3)/2
2006-11-27 06:50:05 · answer #2 · answered by Pascal 7 · 1⤊ 0⤋
-1 will satisfy the answer.
Consider -1 to be the cube root, then;
(-1)*(-1)*(-1) = -1
2006-11-27 07:04:16 · answer #3 · answered by Brenmore 5 · 0⤊ 1⤋
Only one root, I think, -1 because -1 x -1 x -1 = -1
There may be others involving i, the square root or -1
2006-11-27 06:51:18 · answer #4 · answered by JJ 7 · 0⤊ 2⤋
i fully agree with math_kp, except that instead of saying f(-1)=0
after division:
(x+1)(x^2-x+1) =0
so either x+1=0 =>x =-1
or x^2-x+1 =0
=> x = (1+-sqrt(-3)]/2=[1+-irt3]/2
2006-11-27 06:49:35 · answer #5 · answered by anami 3 · 0⤊ 1⤋