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2006-11-26 22:38:50 · 11 answers · asked by Venkateswaran A 2 in Science & Mathematics Mathematics

11 answers

let cube root of 1 be x.
=> x^3 = 1
=> x^3 - 1 = 0
=> (x-1) (x^2 + x + 1) = 0
=> x=1 or x^2+ x+1=0
=> x=1 or x= [1+ i(3)^1/2 ] / 2 or [1- i(3)^1/2 ] / 2
where i is iota, (-1)^1/2
Hence cube root of one has three roots, one real and 2 imaginary. these imaginary roots are called w (omega) and omega square.
1+w +w^2 =0
1* w * w^2 = 1

2006-11-26 23:00:37 · answer #1 · answered by Manjari 2 · 0 0

1

2006-11-27 00:04:25 · answer #2 · answered by Slimm D 3 · 0 0

1

2006-11-26 22:42:07 · answer #3 · answered by ? 2 · 0 1

The cube root of 1 is 1 itself

2006-11-26 22:40:35 · answer #4 · answered by Sankalp P 1 · 0 0

(–1 ± i√3)/2 are cube roots of 1

2006-11-26 22:51:33 · answer #5 · answered by Prasad.S 2 · 0 0

The cube root of 1 is 1. 1 cubed is 1x1x1=1

2006-11-26 22:55:30 · answer #6 · answered by Max 6 · 0 1

1, (i√3-1)/2, and (-i√3-1)/2

2006-11-26 22:49:20 · answer #7 · answered by Pascal 7 · 1 0

(dice root of 25) over 5. 'least confusing kind' skill getting the novel out of the denominator. a million/5 ^a million/3 . Multiply a million/5 with the help of 25/25 so as that the denominator is a proper dice. That makes the numerator equivalent to twenty-5.

2016-11-27 01:11:03 · answer #8 · answered by ? 3 · 0 0

It is just think of the number that when you multi[ply to itself 3 times teh answer is 1 and that is 1

2006-11-26 23:11:31 · answer #9 · answered by jdash01 3 · 0 0

Its '1'
As one / one 3 times is 1.
I hope its clear to you.

2006-11-26 22:42:30 · answer #10 · answered by Mayank 2 · 0 1

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