HARD Challenge Question!!!?

Question

The world record for free hen's egg throwing is 96.90 m, set in 1981. Assuming no air resistance, what would have been the (a) throwing speed; (b) elevation angle; (c) maximum height; (d) time of flight?
(Assume acceleration due to gravity = 10m/s/s)
This question is possible to answer!!!
Please show how you got the question..this would be a great help to me!!
And best of all...best answer gets 10 points!!!!

ok...i understand what everyone is saying...but in the test book these are the answers given...
(a)31.1m/s
(b)45 degrees
(c)+24m
(d)4.4s
if anyone can help show me how they got these anwers it would be a big help

Answer 1

if it is in the text book look it the last few pages

Answer 2

Maximum range is when the angle is 45 degrees

Horizontal velocity is constant and equal to v * cos(45)=v*.7071

Vertical velocity changes but starts at v * sin(45)=v*.7071,
the same as the horizontal velocity.

When the vertical velocity reaches zero, it has traveled for t = v sin(45)/g seconds. Time t also represents the midway point of the flight, at 48.45 meters, which equals v cos(45) * t

Substituting, v cos(45) * v sin(45)/g = 48.45
1/2 v^2 / 10 = 48.45, v^2 = 969, v = 31.1 m/s

Also, distance = velocity * time,
so time = 48.45 / 21.99 = 2.2 seconds halfway through the flight.

Distance (height) = 1/2 g t^2 = 5 * 2.2^2 = 24 meters

QED

Update on 11/30/06: Why the maximum range is at 45 degrees - follow this link for a good explanation:

http://www.physics.ubc.ca/~outreach/phys420/p420_00/darren/web/range/range.html