HARD Challenge Question!!!?

Question

The world record for free hen's egg throwing is 96.90 m, set in 1981. Assuming no air resistance, what would have been the (a) throwing speed; (b) elevation angle; (c) maximum height; (d) time of flight?
(Assume acceleration due to gravity = 10m/s/s)
This question is possible to answer!!!
Please show how you got the question..this would be a great help to me!!
And best of all...best answer gets 10 points!!!!

ok...i understand what everyone is saying...but in the test book these are the answers given...
(a)31.1m/s
(b)45 degrees
(c)+24m
(d)4.4s
if anyone can help show me how they got these anwers it would be a big help

Answer 1

I think you are supposed to assume the minimum velocity possible, which means tossed at a 45 degree angle. Otherwise he could throw it farther by using the same velocity at 45 degrees.

velocity = v, y velocity at time t = v/sqrt(2) - 10t so y velocity is 0 at

t = v/(10sqrt(2))
In time 2t the distance travelled is 96.90, so

96.90 = 2tv/sqrt(2)

These are 2 equations with 2 unknowns, solve for t and v (there may be a careless mistake in the details since I did this fast, but the technique will work)

Answer 2

a numerical result is impossible because there are too many unknown variables (angle of departure, initial height of point of departure,angle of departure, speed of departure)
unless there is information inherent in the (egg throwing ) statement (like standard techniques whereby either angle , speed or height are known) any answer will include unknown variables.


edit
you see, like i told you , there must be something inherent in the statement (egg throw) which is , as sid has showed, that 45 degrees is the optimum throwing angle .
however the format of the question is objectionable, since the angle is required as an answer it implies that it is to be calculated , not deduced from the question.

good luck

Answer 3

Basic Laws of motion !!!

Distance = init-vel x time + 0.5gt^2
96.90 = 0 + 5t^2
t=4.4 sec

No need to solve further, max or efficient (optimal) angle for FARTHEST throw is always 45 deg


Pressed for time
use
v=u+gt
V2=u2 + 2gs
so on...

Answer 4

The problem is, there are an infinite number of solutions. He could have thrown it at any angle between zero and 90 degrees.

Answer 5

There is a very simple mathematical equation for trajectories. So I suggest you look up "trajectory equation" in your physics book, or on-line. Trajectory is symbolized "R". It will give you all of these answers, and quite easily too. Assuming you know some simple trig.