2006-11-26 19:00:51 · 4 answers · asked by Anonymous in Education & Reference ➔ Homework Help
where a and b are not same ( a <> b )
2006-11-26 19:12:20 · update #1
ab=a+b
ab-a-b+1=1
(a-1)(b-1)=1
a=(1/(b-1))+1
If a is not 1 and b is not 1, then you can find a if you know b and vice versa. Therefore, if a is anything other than 1, you can find b that works and vice versa.
2006-11-26 19:14:57 · answer #1 · answered by bictor717 3 · 0⤊ 0⤋
If a + b = ab, both a and b = 2. (2 + 2 = 2 x 2)
That's it, unless zero is a rational number--if it is, then the answer is, a and b can both equal 2, OR a and b can both equal zero.
2006-11-27 03:11:47 · answer #2 · answered by Anonymous · 0⤊ 0⤋
b=a/(a-1)
=> for every odd 'a', we get a rational number for 'b'.
So, there are infinte possible pairs.
If a and b were integer, then I guess 0,0 and 2,2 are the only two possible values
2006-11-27 03:19:59 · answer #3 · answered by yousuf f 1 · 0⤊ 0⤋
0 for both A and B
2 for both A and B
2006-11-27 03:10:15 · answer #4 · answered by king p 2 · 0⤊ 0⤋