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2006-11-26 16:59:46 · 6 answers · asked by Mileesh M 1 in Science & Mathematics Mathematics

6 answers

There is no ordered pair {a,b} which solves both equations

if a+b = a-b , then 2b = 0 or b = 0 and a is anything

But the second equation is not defined for b=0, no matter what a is (specifically, a/b is not defined for b=0)

2006-11-26 17:35:19 · answer #1 · answered by Scott R 6 · 2 0

a + b = a - b
ab = a/b

We can transpose everything to the left, and multiply the LCD when possible
2b = 0
ab² - a = 0

We see that
b = 0
a(b² - 1) = 0

We substitute b to the second equation
a(0 - 1) = 0

Therefore,
a = 0

But
ab = a/b,
0·0 = 0/0

As you can see, division by zero is undefined, so there is no solution...

^_^

2006-11-26 23:33:00 · answer #2 · answered by kevin! 5 · 0 0

a + b = a - b
b = 0
a = any number

ab = a/b
ab² = a
ab² - a = 0
a(b² - 1) = 0
a = 0 or b = ±1

So combining both solutions
a = 0, b = 0

2006-11-26 17:21:07 · answer #3 · answered by Wal C 6 · 0 1

a=0 b=0

a+b=10 points!

2006-11-26 17:10:26 · answer #4 · answered by orlandobillybob 6 · 0 1

variable

2006-11-26 17:07:08 · answer #5 · answered by Maribelle P 1 · 0 1

ZERO???

2006-11-26 17:01:15 · answer #6 · answered by givemeagoodanswer 1 · 0 1

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