There is no ordered pair {a,b} which solves both equations
if a+b = a-b , then 2b = 0 or b = 0 and a is anything
But the second equation is not defined for b=0, no matter what a is (specifically, a/b is not defined for b=0)
2006-11-26 17:35:19
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answer #1
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answered by Scott R 6
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2⤊
0⤋
a + b = a - b
ab = a/b
We can transpose everything to the left, and multiply the LCD when possible
2b = 0
ab² - a = 0
We see that
b = 0
a(b² - 1) = 0
We substitute b to the second equation
a(0 - 1) = 0
Therefore,
a = 0
But
ab = a/b,
0·0 = 0/0
As you can see, division by zero is undefined, so there is no solution...
^_^
2006-11-26 23:33:00
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answer #2
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answered by kevin! 5
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0⤊
0⤋
a + b = a - b
b = 0
a = any number
ab = a/b
ab² = a
ab² - a = 0
a(b² - 1) = 0
a = 0 or b = ±1
So combining both solutions
a = 0, b = 0
2006-11-26 17:21:07
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answer #3
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answered by Wal C 6
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a=0 b=0
a+b=10 points!
2006-11-26 17:10:26
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answer #4
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answered by orlandobillybob 6
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0⤊
1⤋
variable
2006-11-26 17:07:08
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answer #5
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answered by Maribelle P 1
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ZERO???
2006-11-26 17:01:15
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answer #6
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answered by givemeagoodanswer 1
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0⤊
1⤋