Solve the following system of equations: 3y +1 =2(x+8) AND 3y +5 =2x - 4?

Question

Here's my question... am I supposed to use the Addition/Substitution/graphing method for these two equations or am I supposed to decide whether they are both correct or if one of them is false. And if I am supposed to decide if they are correct or false, don't I need something that says X equals a specific number or Y equals a specific number? I am confused on what to do with this problem.

Answer 1

well to solve the first equation (its a line plot)
3y+1[-1]=2x+16[-1]
3y=2x+15
if x=0, y=5 (y intercept)
if y=0, x=-7.5 (x intercept)

the second line graph
3y+5[+4]=2x
3y+9=2x
if x=0, y=-3
if y=0, x=4.5

Now, these lines are not equal, but do you have to plot both lines to prove? Your question is not clear.

Answer 2

The first equation can be reduced or simplified as follows:
3y + 1 = 2(x+8)
3y + 1 = 2x + 16
3y = 2x + 15

The second equation reduces as follows:
3y+ 5 = 2x -4
3y = 2x -9

Both of the reduced equations are the same on the left side, therefore:
2x + 15 = 2x -9
or 15 = -9

Since the above answer is nonsense, one of the equations is false. There is not enough information in your question to figure out which one is false. I suspect your teacher just wants you to use the method that's easier for you, and gives you the correct answer.

Answer 3

First remedy one equation for Y 5x = y + 6 Subtract 6 from the two components 5x - 6 = y interior the 2d equation substitute the fee of y interior the situation of y. 2x - 3(5x - 6) = 4 remedy for x first distribute the -3 2x-15x+18 = 4 combine like words -13x+18=4 subtract 18 from the two components -13x=-14 Divide with the aid of -13 on the two components x=-14/13 Now substitute the fee of x interior the 1st equation that fluctuate into solved for y 5(14/13) - 6 = y y=-8/13

Answer 4

Eqn of line is y=mx + c where m is the slope

eq 1 becomes

3y = 2x + 15
=> y = (2/3)x + 5
hence m = 2/3
eq 2 becomes
3y = 2x - 9
=> y = (2/3)x - 3
hence m=2/3

Since both lines have same slope, they are parallel to each other and hence do not cross at any point. So they cannot be solved simultaneously.
Eqns are NOT false, they are just parallel to each other ad hence no solution exists.

Answer 5

first equation y=7 and x=3
2nd y=3 and x=9

not sure that helps?

Answer 6

breezieone777 Wow!Your Extra News here!
★※★ http://www.osoq.com/funstuff/extra/extra03.asp?strName=breezieone777