a basketball player shoots the ball with a velocity of 13.6 ft/s at an angle of 33.1 degrees with the horizontal. to the nearest tenth, find the magnitude of the horizontal component of the resultant vector.
choices
A.5.7ft/s
B. 3.7ft/s
C.7.4ft/s
D.11.4ft/s
2006-11-26 16:13:15 · 2 answers · asked by Dennis B 1 in Education & Reference ➔ Homework Help
This is a simple trig question.
The horizontal component of the vector can be found using the cosine:
cos 33.1 = vh / v
cos 33.1 = vh / 13.6
vh = 13.6 * cos 33.1
vh = 11.39
vh = 11.4 ft sec.
2006-11-27 00:54:03 · answer #1 · answered by ³√carthagebrujah 6 · 0⤊ 0⤋
magnitude of component=velocity* sin angle
=13.6 *sin 33.1
=13.6*0.5461
=7.4523
~7.4
2006-11-27 09:04:15 · answer #2 · answered by shivar_007 1 · 0⤊ 0⤋