Algebra 2 help?

Question

Find the Zeros of the fuction by rewriting the function in intercept form.

y=3x^2 + 2x


and this one


y=12x^2+8x-15
I dont get it - help me please

Answer 1

ok the zeros are where the line intercepts the x-axis. so you need to solve for x. the easiest way to do it is to graph it in your calculator, and find the x intercept.

Answer 2

The zeros are when the curve intercepts the X-axis or when y is equal to zero. The age old solution is the Quadratic Formula.

First set y=0 then use the quadratic formula:

x = [-b(+/-)sqrt(b^2-4ac)]/2a

It's difficult to properly display a formula in this format. If you want a better representation type in quadratic formula at www.wikipedia.org.)

The coefficients a, b, and c are when ax^2+bx+c=0.

In your first equation a = 3, b = 2 and c = 0.
For your second equation a = 12, b = 8, and c = -15.