If P(x)=(2x-3)(x-5)(x+1), where does the function cross the x-axis?

0 ⤊

If P(x)=(2x-3)(x-5)(x+1), where does the function cross the x-axis?

2006-11-26 15:33:43 · 4 answers · asked by jere 1 in Science & Mathematics ➔ Mathematics

4 answers

if cuts the x axis when p(x) = 0

that is 2x-3 = or x= 3/2

2nd point x-5 =0 or x = 5

3rd point x+1 = 0 or x = -1

2006-11-26 15:36:10 · answer #1 · answered by Mein Hoon Na 7 · 0⤊ 0⤋

P(x) = (2x - 3)(x - 5)(x + 1)
cuts the x - axis when P(x) = 0
ie when (2x - 3)(x - 5)(x + 1) = 0
ie when x = -1, 3/2 and 5

2006-11-26 23:36:21 · answer #2 · answered by Wal C 6 · 0⤊ 0⤋

Where does P(x) become 0?
Answer: when x=3/2, 5, -1

2006-11-26 23:38:45 · answer #3 · answered by kellenraid 6 · 0⤊ 0⤋

it crosses the x-axis whenever the function is equal to zero. since the function is already factored, it's easy to find when the function is zero.

x= 3/2
x= 5
x= -1

2006-11-26 23:37:10 · answer #4 · answered by Joel P 2 · 0⤊ 0⤋