8t^2 - 32a
2006-11-26 15:22:35 · 7 answers · asked by tigertank702 1 in Science & Mathematics ➔ Mathematics
8(t-2sqrt(a))(t+2sqrt(a))
2006-11-26 15:29:52 · answer #1 · answered by Anonymous · 0⤊ 0⤋
8t^2 - 32a
= 8 (t^2 - 4a)
However, if the 'a' is actually 't', factor out 8t.
8t^2 - 32t
= 8t(t - 4)
2006-11-26 23:35:40 · answer #2 · answered by Anonymous · 0⤊ 0⤋
easy,first of all,you do it like this.
8t^2-32a=8(t^2-4a)
since a=(squre root of a)^2
so it can be wrtitten as the following
8(t-2sqrt a)(t+2sqrt a)
2006-11-26 23:34:20 · answer #3 · answered by peterwan1982 2 · 0⤊ 0⤋
If it is actually supposed to be 8t^2 - 32t, then it's
8t(t-4)
As given, it is
8(t^2-4a)
If you want radicals, it's
8(t-2a^(1/2))(t+2a^(1/2))
2006-11-26 23:30:42 · answer #4 · answered by airtime 3 · 0⤊ 0⤋
take 8 common
8(t^2-4a)
= 8(t-2sqrt(a))(t+2 sqrt(a))
2006-11-26 23:32:00 · answer #5 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
8(t^2 - 4a)
2006-11-26 23:39:29 · answer #6 · answered by Naval Architect 5 · 0⤊ 0⤋
8(t^2-4a)
2006-11-26 23:31:07 · answer #7 · answered by arleth m 2 · 0⤊ 0⤋