sove this quadratic equation?

Question

2p^3 = 2p(p + 2)

Answer 1

2p^3 = 2p(p + 2)
2p^3-2p(p+2)=0
2p(p^2-p-2)=0
2p(p-2)(p+1)
p=0
p-2=0
p=2
p+1=0
p=-1

roots are
p=0, 2, -1

Answer 2

You can see immediately that p=0 is a solution.

Put in standard form:
2p^3 -2p(p+2) = 0
p(2p^2-2p-4) = 0

so p=0 is a solution, now factor the quadratic, pull out a 2 first

p^2-p-2 = 0 , roots -2, 1
(p-2)(p+1)

Thus the complete factorization is
p(p-2)(p-1)=0

Answer 3

2p^3 = 2p(p + 2)
2p^3 = 2p^2 + 4p

Bring all of the numbers to one side.
2p^3 - 2p^2 - 4p = 0

Factor out 2p.
2p(p^2 - p - 2) = 0

Simplify the equation.
2p(p - 2)(p + 1) = 0

Therefore,
2p = 0 or p - 2 = 0 or p + 1 = 0
p = 0 or p = 2 or p = -1

In short,
p = 0, 2, -1

Answer 4

it rather is a appropriate sq. trinomial easily. you will discover ways to acknowledge those the greater you practice polishing off the sq.. x^2 - 2x + one million = 0 (x - one million)^2 = 0 From right here, take the sq. root of the two facets. The sq. root of 0 is plus or minus 0, yet +0 and -0 are the comparable, so x - one million = 0 x = one million