What is the vertex for the parabola y=2x^2-8x+15?
Please explain with as much detail as possible.
2006-11-26 15:15:41 · 4 answers · asked by Eric 2 in Science & Mathematics ➔ Mathematics
The vertex of a parabola occurs at its minimum or maximum point (whichever is appropriate). A concave up parabola has a minimum; a concave down parabola has a maximum. From our formula, we are looking for a minimum. There is a formula to find the vertex, which I have forgotten. But using calculus and derivatives, the vertex occurs at the point (2, 7).
2006-11-26 15:20:55 · answer #1 · answered by Dan 3 · 0⤊ 0⤋
y=2x^2-8x+15
y'=4x-8=0
4x=8
x=2
y=2*2^2-8*2+15=8-16+15=7
vertex is at (2,7)
2006-11-26 23:18:30 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
x = - (-8) / (2*2) = 2
y = 2*2^2 - 8*2 +15 = 7
2006-11-26 23:19:06 · answer #3 · answered by Anonymous · 0⤊ 0⤋
are you in college or highschool if your in college i cant help you if highschool what grade and the answer is 7
2006-11-26 23:21:56 · answer #4 · answered by nataliaschick 2 · 0⤊ 0⤋