I am a prime number between 40 and 50.If you add one to me, the sum of the prime factors of that composite number 11.What am I?
2006-11-26 14:48:57 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
47
Edit: intel_knight, those values are the ones that don't work. 41+1 = 42 = 2*3*7, and 2+3+7 = 12 ≠ 11. Similarly, 43+1 = 44 = 2*2*11, and 2+2+11 = 15 ≠ 11.
yupchagee, since when is 44 a prime number?
2006-11-26 14:52:14 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋
The prime is 47
47 plus 1 equals 48
prime factors work this way
2 x 24 = 48
2 x 2x12 =48
2 x 2 x 2 x 6 = 48
2 x 2 x 2 x2 x3 =48
2 + 2 + 2 + 2 + 3 + 11
Carl
2006-11-26 14:57:28 · answer #2 · answered by Carl P 7 · 0⤊ 0⤋
There are exactly three primes in the range of interest: 41, 43, and 47. Of these, only 47 fits the problem (2+2+2+2+3).
2006-11-26 14:51:59 · answer #3 · answered by Anonymous · 2⤊ 0⤋
the prime numbers between 40 and 50 are 41, 43, and 47
41+1=42....prime factors are 2,3, and 7....they add up to 12......so 41 is not an answer!
43+1=44....prime factors are 2,2, and 11...they add up to 15......so 43 is not and answer.
47+1=48....prime factors are 2,2,2,2, and 3...they add up to 11.....so 47 is the answer.
ANSWER IS 47
2006-11-26 14:55:26 · answer #4 · answered by pzratnog 3 · 0⤊ 0⤋
44: 44+1=45=3*3*5; 3+3+5=11
47: 47+1=48=2*2*2*2*3; 2+2+2+2+3=11
2006-11-26 14:51:43 · answer #5 · answered by yupchagee 7 · 0⤊ 1⤋
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2016-05-23 07:31:42 · answer #6 · answered by Anonymous · 0⤊ 0⤋
either 41 or 43, you do the math
2006-11-26 14:51:02 · answer #7 · answered by Anonymous · 0⤊ 1⤋
Is this a real question that can be solved with REAL MATHEMATICS!?? or only a trick question??
2006-11-26 14:51:33 · answer #8 · answered by mrmilasan 1 · 0⤊ 1⤋