Let width = x, length = 2x.
Perimeter = x + 2x + x + 2x = 240
So 6x = 240
So x = 40
So width is 40, length is 80, so area = 3200 square feet.
2006-11-26 14:26:36
·
answer #1
·
answered by stephen m 4
·
2⤊
0⤋
Start with the first sentance. The width is 10 feet longer than 3/5 the length. Change that to an equation W = 10 + 3/5*L, where W is width and L is length. "Is" in a sentance always means equal. Longer in this instance means add. Three fifths the length means multiply 3/5 by the length. Take the next sentance and make it into an equation. The equation for perimeter is 2W + 2L = perimeter. So: 2W + 2L = 500 feet, where W is width and L is length again. The area of a rectangle is L*W. Use the frist 2 equations to solve for L and W. Then use L and W to find the area.
2016-05-23 07:29:44
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
Let width equal x. Thus, length equals 2x. Using variables, the perimeter of a rectangle is twice the sum of the width and lenght; that is, 6x.
6x = 240 feet
x = 40 feet
The area of a rectangle is length times width.
40 * (2 * 40) = 40 * 80 = 3200 square feet
2006-11-26 14:28:42
·
answer #3
·
answered by Dan 3
·
0⤊
0⤋
so we have 2x + x + 2x + x = 240
then 6x = 240
x = 40
then length = 2x = 80
width = x = 40
area = length x width = 80 x 40 = 3200 ft^2
2006-11-26 14:29:22
·
answer #4
·
answered by Anonymous
·
0⤊
0⤋
3,200 Square ft. The rectangle is 80ft. long by 40ft. wide.
(The length is twice the width!) Add up all for side, that comes to 240ft. The area is the Lenght x the Width, so 80 x 40 = 3,200Sq. ft.
2006-11-26 14:30:39
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
3,200 square feet
perimeter = twice length + twice width
but we are told length = twice width
so perimeter = six times width
as perimeter is 240 feet, width = 40 feet
and therefore length = 80 feet
so area = length x width
= 80 x 40 square feet = 3,200 square feet
2006-11-26 14:26:48
·
answer #6
·
answered by Anonymous
·
0⤊
0⤋
Ans Say length is L and Width is b
According to condition L = 2b
Perimeter = 2(L+b) =2(2b+b)=240
so b = 40ft
L=2b=2(40) =80ft
Area = L(b)=80(40) =3200ft^2 Ans.
2006-11-26 14:31:07
·
answer #7
·
answered by aminnyus 2
·
0⤊
0⤋
Let width be w ft
Therefore length = 2w ft
So P = 2l + 2w
= 4w + 2w
= 6w
= 240
So w = 40 ft
and l = 2w
= 80 ft
Area = lw
= 40 x 80
=3200 ft²
2006-11-26 14:29:09
·
answer #8
·
answered by Wal C 6
·
0⤊
0⤋
So L=2W. Using the perimeter given...
length+length+width+width=perimeter
2W+2W+W+W=240
6W=240
W=40
If width is 40 feet and length is twice this then the length is 80.
So area=length*width
A=40*80
A=3200 square feet
2006-11-26 14:29:54
·
answer #9
·
answered by TiCo 1
·
0⤊
0⤋
its perimiter is 240 ft so 1 long side + 1 short side is 120 ft (half the perimiter)
the long side is twice the length of the short side so they are 80 ft and 40 ft (adding up to 120)
so the area is 40 x 80 = 3200 ft
2006-11-26 14:27:25
·
answer #10
·
answered by hot.turkey 5
·
0⤊
0⤋