factor completely?

1 ⤊

125p^3 + 64

2006-11-26 14:16:53 · 2 answers · asked by mzmuffin40155 2 in Science & Mathematics ➔ Mathematics

2 answers

What you should notice is that everything there is a cube.
So we have: (5p)^3 + 4^3
Now, a^3 + b^3 = (a+b)(a^2 - ab + b^2)
So we get (5p+4)(25p^2 - 20p + 16). We can't factorise that any more.

2006-11-26 14:24:45 · answer #1 · answered by stephen m 4 · 0⤊ 0⤋

125p^3 + 64 = (5p+4)(25p^2 - 20p + 16).]

2006-11-26 22:54:11 · answer #2 · answered by locuaz 7 · 1⤊ 0⤋