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The normal boiling point of water is 100C and deltaHvap is 44.0kJmol-1.

a) 0.44 J K-1 mol-1
b) 440 J K-1 mol-1
c) 847 J K-1 mol-1
d) 161 J K-1 mol-1
e) 118 J K-1 mol-1

2006-11-26 14:12:07 · 1 answers · asked by adam v 1 in Science & Mathematics Chemistry

1 answers

deltaG = deltaH - TdeltaS

When delta G equals zero,

deltaH = TdeltaS

deltaS = deltaH/T = (44.0 kJ/mol)/373K = 0.11796 kJ/mol.K

So I'd pick e.

2006-11-30 08:35:40 · answer #1 · answered by wibblytums 5 · 0 1

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