-y^2 + 9y - 20
2006-11-26 14:03:19 · 13 answers · asked by mzmuffin40155 2 in Science & Mathematics ➔ Mathematics
take - common
-(y^2-9y+20)
-(y^2-5y-4y+20)
-(y(y-5)-4(y-5))
-(y-4)(y-5)
2006-11-26 14:06:51 · answer #1 · answered by sidharth 2 · 0⤊ 0⤋
First factor out a negative 1.
-1(y^2-9y+20)
What factors of 20 add up to be -9? -5 and -4
-(y-5)(y-4)
2006-11-26 14:09:26 · answer #2 · answered by TiCo 1 · 0⤊ 0⤋
ok first to start out, u have -y^2 + 9y - 20
1st step. divide all by -1 -y^2 + 9y - 20/ -1= y^2 - 9y + 20
2nd step. what two numbers mulitply each other to get 20 but also add up to get -9? -5 & -4. (-5 * -4= 20, -5 + -4= -9) and so, (y-5)(y-4) is ur answer
2006-11-26 14:16:26 · answer #3 · answered by game_revolutionist08 2 · 0⤊ 0⤋
Factor out the -1 so you get -(y^2 - 9y + 20). Factor the polynomial. -(y - 4)(y - 5)
2006-11-26 14:07:38 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I belive it is -1(y - 4)(y - 5).
-1*(y - 4) = (-y + 4)
(-y + 4)*(y-5) = -y^2 + 5y + 4y -20 = -y^2 + 9y -20
2006-11-26 14:07:51 · answer #5 · answered by Edgar Greenberg 5 · 0⤊ 0⤋
-y^2 + 9y - 20
(-y+5)(y-4)
2006-11-26 15:15:29 · answer #6 · answered by yupchagee 7 · 0⤊ 0⤋
-y^2 + 9y - 20
= -(y^2 - 9y + 20)
= - (y - 5)(y - 4)
= (y - 4)(5 - y)
2006-11-26 14:08:00 · answer #7 · answered by Wal C 6 · 0⤊ 0⤋
-y^2+9y-20
= -y^2+5y+4y-20
= -y(y-5)+4(y-5)
= (y-5)(-y+4) Ans.
2006-11-26 14:08:57 · answer #8 · answered by aminnyus 2 · 0⤊ 0⤋
-y^2+9y-20
-1(y^2-9y+20)
-1(y-5)(y-4)
those are the steps in order
the last one is the answer
DO you udnerstand it now?
2006-11-26 14:10:18 · answer #9 · answered by pirate_ninjarawr 2 · 0⤊ 0⤋
-y^2 + 9y - 20
-y^2+4y+5y-20
-y(y-4)+5(y-4)
(-y+5)(y-4)
-(y-5)(y-4)
2006-11-26 14:07:06 · answer #10 · answered by Dupinder jeet kaur k 2 · 1⤊ 1⤋