factor completely?

2 ⤊

x^2yz + xy^2z + xyz

2006-11-26 14:00:40 · 2 answers · asked by mzmuffin40155 2 in Science & Mathematics ➔ Mathematics

2 answers

The least xs in any term is 1; same for y and z. So there is a factor of xyz. The first one needs another x; the second another y; the third doesn't need anything, so you get:
xyz(x+y+1).

2006-11-26 14:04:10 · answer #1 · answered by stephen m 4 · 1⤊ 0⤋

x^2yz + xy^2z + xyz
xyz(x+y+1)

2006-11-26 22:04:45 · answer #2 · answered by Dupinder jeet kaur k 2 · 1⤊ 0⤋