Problem:
p(-2) if p(x) = 3x(4th power) + 3x(3rd power) + 7x - 10
Answers:
-10
0
14
46
2006-11-26 13:57:39 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
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You're a fag.
2006-11-26 14:05:55 · update #1
p(x) = 3x^4 + 3x^3 + 7x - 10
p(-2) = 3(-2)^4 + 3(-2)^3 + 7(-2) - 10
= 48 - 24 - 14 - 10
= 0 ← option B
2006-11-26 14:01:06 · answer #1 · answered by Wal C 6 · 0⤊ 1⤋
14
2006-11-26 22:05:52 · answer #2 · answered by profitmessenger 2 · 0⤊ 0⤋
Replace x with -2.
3(-2)^4 + 3(-2)^3 + 7(-2) - 10
3(16)+ 3(-8) - 14 -10
48 -24 -14 -10
24 - 24 = 0 the 2nd choice
2006-11-26 22:07:28 · answer #3 · answered by dark&pure? 3 · 0⤊ 0⤋
p(x)=3x^4 + 3x^3+7x-10
so P(-2)= 3(-2)^4+3(-2)^3+7(-2)-10
=0 is the correct Ans.
2006-11-26 22:05:05 · answer #4 · answered by aminnyus 2 · 0⤊ 0⤋