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solved this problem on my own already, but I'm not sure if it's correct. Can someone check to see if I did it right? Click here: http://i3.photobucket.com/albums/y92/musicis4fools2/physicspulley.jpg

2006-11-26 13:32:05 · 2 answers · asked by graycl0ud 1 in Science & Mathematics Mathematics

2 answers

From what I can see you forgot the moment of inertia of the pulley.
Remember Torque = I*alpha. TensionxR = I*a/r. There will be another acceleration term from this torque.

EDIT: No, wait sorry. I jut didn't see it. Ha it was right there in part i) The photo's kinda hard to read. Yeah, It's good.

2006-11-26 13:37:25 · answer #1 · answered by Edgar Greenberg 5 · 0 0

enable the stress interior the string is T Newton and the acceleration of the gadget is a m/s^2 with the aid of balancing the forces on each and each mass:- =>12g - T = 12a -----------(i) & T - 4g = 4a -------------(ii) with the aid of (i) + (ii) :- =>8g = 16a =>a = g/2 = 4.9 m/s^2

2016-10-13 04:25:06 · answer #2 · answered by seabrooks 4 · 0 0

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