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2006-11-26 13:30:07 · 12 answers · asked by Anonymous in Education & Reference Homework Help

12 answers

if it has three or more digits, and if it ends in zero.

2006-11-26 13:31:23 · answer #1 · answered by Anonymous · 0 2

If you want the answer to be a whole number then...
You need a number at least 3 digits long, ending in 00 such as:
200
2500
34500
If you divide these numbers by 100, just knock off the two zeros for your answer:
2
25
345

2006-11-26 13:36:17 · answer #2 · answered by Anonymous · 0 0

well -- if the rule for divisibility by 10 is that it has at least two digits and that it ends in zero, what do you think the rule would be for 100???

2006-11-26 13:33:28 · answer #3 · answered by Anonymous · 0 0

Just knock off the first two Zeros on the Number you are dividing 100 by, and that is the answer of how many times 100 goes into it.

2006-11-26 13:32:40 · answer #4 · answered by hey2a 3 · 0 0

Wikipedia: Divisibility rule
... 4 (This is because 100 is divisible by 4 and so adding hundreds, thousands, etc. ... This is also true for numbers such as 4 and 25, except that once a ...en.wikipedia.org/wiki/Divisibility_rule

2006-11-26 13:32:10 · answer #5 · answered by Anonymous · 0 1

The last two digits of that number must be zero and the digit has at least three numbers

2006-11-26 21:16:44 · answer #6 · answered by Anonymous · 0 0

you're able to desire to remedy 3 distinctive situations right here. one million. X is divisible via 3. subsequently X^2 is likewise divisible via 3. Subtracting one million from a variety divisible via 3 leaves the variety not divisible via 3. 2. X is divisible via 3, X+one million isn't. Squaring (X+one million) promises X^2+2X+one million. utilising the coolest judgment above, X^2 is divisible via 3, 2X is divisible via 3. Subtracting the only million leaves you with X^2+2x, a variety divisible via 2. 3. X is divisible via 3, X+2 isn't. going for the time of an analogous good judgment as (2), you have X^2+4X+4. Subtracting one million leaves you with X^2+4X+3, divisible via 3

2016-12-29 13:06:24 · answer #7 · answered by Anonymous · 0 0

at least the last two digits must be zero and the number must have more than two digits

2006-11-26 13:46:11 · answer #8 · answered by piggip05 2 · 0 0

the last two digits must be 00.

2006-11-26 13:32:10 · answer #9 · answered by banjuja58 4 · 3 0

in ends in 2 zeros:
100
200
300 (etc)

2006-11-26 13:32:19 · answer #10 · answered by hot.turkey 5 · 1 0

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