Help me with this?

Question

Simplify this for me.

2x(2x^2y)^3(3xy^4)^2
In word form
2x (times 2x to the 2nd y) to the 3rd(times 3xyto the 4th) to the 2nd.

If you don't know how to do this, don't bother answering this.

Answer 1

If you have lots of terms inside brackets which need to be raised to a power, just raise each individual term to that power.
So 2x(2x^2 y)^3 (3xy^4)^2 =
2x * (2^3 * (x^2)^3 * y^3) * (3^2 * x^2 * (y^4)^2)
= 2x * 8 * x^6 * y^3 * 9 * x^2 * y^8
= (2*8*9)*(x * x^6 * x^2) * (y^3 * y^8)
= 144x^9y^11.

Answer 2

2x(2x²y)³(3xy^4)²

= 2x * 8x^6 y³ * 9x² y^8
= 144 x^9 y^11