physics book weighing 20N slides at constant speed down a ramp inclined at 30 degrees to the horizontal. what is the force of friction acting on the book?
2006-11-26 12:36:06 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
you need to work out the force of the book thats heading down the ramp using triginometry. as its a constant speed, there is no acceleration, so the friction must be equal to the force pointing down the slope
2006-11-26 12:44:26 · answer #1 · answered by andygos 3 · 0⤊ 0⤋
Let mass =m, then weight=mg=20 N
Since it slides down uniformly, the friction force equals the inclined component, or
friction=mg sin(theta)
=20 N . sin(30)
=10 N
2006-11-26 13:05:19 · answer #2 · answered by mathpath 2 · 0⤊ 0⤋
gravity, the ramp, and air resistance, those are the forces acting on the book
2006-11-26 14:12:04 · answer #3 · answered by Angels Eyes 2 · 0⤊ 0⤋
same as in newton first law
2006-11-26 14:33:22 · answer #4 · answered by Anonymous · 0⤊ 0⤋