Can Someone Please Breakdown How I Need To Solve This Problem?

Question

Create the equation that goes with the graph.
Ok, the graph looks kind of like this -|-.
The first point that lies directly on the X axis is located at (2,0)
The second point is located at (-2,-2)

Can someone PLEASE break this problem down into how I would be able to solve it. I'm desperate and my math grade is slipping. I have 5 other problems but I just need to know how to get started. Any help is appreciated

I need to find it out in a y= equation.

so, y= .5x?

Yes it's a straight line

Answer 1

Please calm down. Now do you want the line between (2,0) and (-2,-2) The way I do it is to get the point vector solution of the line and eliminate t. The point is (2,0). The vector is <-2 - 2, -2 -0>. Just subtract the first coordinate from the second. So the vector is <-4, -2>
Now set up the point vector equation describing the postion of the graph at time t.
Just point + vector*t in component form.
The x-components: x = 2 - 4t
The ys: y = 0 - 2t

There, that is it. But some nasty professors don't like this form, so we'll eliminate t. We plug y = -2t into first equation and get x = 2 + 2y.
2y = x - 2. y = x/2 -1.

Answer 2

Okay, so you're given two points on a line and they want you to find the equation of the line. That means you use the slope formula to find the slope of the line. The formula is: (y2-y1)/(x2-x1) where x1=2, y1=0 (from the point (2,0)), and x2=-2, y2=-2 (from the point (-2,-2). So you plug the numbers into the formula: (-2 - 0)/(-2 - 2) = -2/-4 = 1/2. So the slope equals 1/2, or 0.5. Now, you use the point-slope formula, which is y - y1 = m(x - x1), where m is the slope. So, using the same numbers from above, you plug them into the equation: y - 0 = 1/2 (x - 2). Now distribute the 1/2, so you get y = 1/2x - 1, which should be the answer. Tell me if you need a more in-depth explanation.

Answer 3

First find the slope. It is the (change in y)/(change in x) also called m thus m = (0- -2)/(2- -2) = 2/4 or 1/2. Then plug this into the slope intercept form model y = mx + b and you get y = 1/2x + b. Then use one of the points to find b. I would use 2 for x and 0 for y. Thus you get 0 = 1/2(2) + b and 0 = 1 + b. We know from this that b = -1 and the equation is y = 1/2x -1.

Answer 4

ok so you have the graph right 2,0 So you would go two horizontaly to the right. and0 means you just plot the point on the line at the twwo horizontal. -2,-2 means you go to the left two slotsand down two spots an plot the point.

Answer 5

First you would find the slope.
Then you would plug the slope into the formula y=mx+b. (m=slope)
Then take one of the points and put in that formula for x & y to solve for b.
Once you have m & b, you then have your formula.

Example...
Two points - (0,0) and (1,2)
Slope will equal 2...change in y over change in x
Now put in slope and one of the points to solve for b (b is y-intercept)...
0=2(0) + b
b=0
Final formula: y=2x + 0

Answer 6

if it's a straight line, it's y=bx+a
First, figure out the slope b - divive difference in y's between two points by difference of x's. answer should be 0.5.

Then figure out the intercept a so that y=0 when x=2