Problem: 4x+5y<9
y>-7
y>-7
Have no idea how to graph for the first equation. I can graph the second and the third one though. I get y<4/5x+9/5 but I don't know what to do next. Please help.
2006-11-26 11:49:10 · 3 answers · asked by Jeffiner 2 in Science & Mathematics ➔ Mathematics
You are graphing y < -4/5 x + 9/5
On the y-axis, above zero, graph 1 4/5 (a little less than 2). From that point, move down 4 squares and right 5 squares and put another point. Connect this point with the 1 4/5 on the y-axis and draw a dotted line between them. Shade BELOW this line.
2006-11-26 11:53:42 · answer #1 · answered by MollyMAM 6 · 0⤊ 0⤋
To get an accurate graph for the boundary line 4x + 5y = 9, it's best to pick numbers for x and y that make it come out even and connect them, since the y-intercept is not an integer. For example, if x=1, y=1 so (1,1) is on the graph
If x = 6 then y = -3 [24 - 15 = 9] so (6, -3) is on the graph.
Plot these and carefully connect them with a line. (It will be a dashed (dotted) line because it originally was <, not < or = to)
2006-11-26 11:55:29 · answer #2 · answered by hayharbr 7 · 0⤊ 0⤋
they're inequalities.
plot y=(9-4x)/5 and shade area under it
2006-11-26 11:54:09 · answer #3 · answered by Anonymous · 0⤊ 0⤋