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I need to know what is the step before gettin to the simplest form of the cube root of 27x^4? i know the answer is 3x^4/3 but what was it before that ( I think its 9lx^2l, but i dont know). ANy one can tell me/ show me the steps.

2006-11-26 11:42:20 · 4 answers · asked by Jeff Mad. 2 in Science & Mathematics Mathematics

4 answers

There are no in between steps here. The cube root of 27 is 3 and the cube root of x^4 is x^4/3

2006-11-26 11:46:52 · answer #1 · answered by MollyMAM 6 · 0 0

cube root of 27x^4 = cube root(27) times x^ (4 /3)
???

2006-11-26 11:46:50 · answer #2 · answered by cfpops 5 · 0 0

cube root of 27 is 3

cube root of x^4 is x^(4*1/3)

2006-11-26 11:45:11 · answer #3 · answered by Anonymous · 0 0

(27*x^4)^(1/3) = 27^(1/3)*x^(4/3)

2006-11-26 11:46:08 · answer #4 · answered by Anonymous · 0 0

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