A Physics Problem.?

Question

A constant F is applied to a mass m intially heading east with v intial until velocity is negative inital the time is 2t what the total distance?



First half of movement.... velocity goes from v to 0
Time = t, mass = m, v goes to 0
Impulse = Ft = m(v - 0) = mat (Momentum is Impluse)
a = v/t
One way distance = vt - 1/2(v/t)(t^2)
= vt - vt/2 = vt/2
Two way distance = 2(vt/2) = vt

Answer 1

What you have so far is correct. If the problem is asking for two-way distance (call it s) in terms of F, m and v, then you can substitute F/m for a:
s = vt = v^2/a = mv^2/F
Note the numerator is twice the kinetic energy, which checks because work = F*distance. The applied force F did .5mv^2 negative work for distance s/2 and the same magnitude positive work for s/2.
I hope this is what you were looking for, since otherwise I don't know what your question is.

Answer 2

the galaxies rotate at speeds inconsistent with their obvious mass is with the help of the fact we do see all of it. i'm touching on it as being the theoretical darkish be counted. There are very stable proofs that shows that darkish be counted exist. One the is the inconsistent velocity of and obvious mass. darkish be counted makes up approximately seventy 5% to eighty% of the issue in the Universe...