Silver has two isotopes 107/47Ag has a mass of 106.905amu (52.00%), and 109/47Ag has a mass of 108.905amu (48.00%). What is the mass of silver
2006-11-26 11:02:51 · 5 answers · asked by lovejessyloot 1 in Science & Mathematics ➔ Chemistry
With this you must use standard deviation, by multiplying each mass by its frecuency.
average atomic mass Ag=
106,905amu*0,5200 + 108,905amu*0,4800 =
55,60amu + 52,27amu =
107,9 amu is the average atomic mass of one Ag atom
2006-11-26 11:23:28 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The reported mass of natural elements is the abundance weighted mass average of each natural isotope.
So for this example:
abundance 107Ag X mass 107Ag + abundance 109Ag X mass 109Ag = Mass Ag
0.52 x 106.905 + 0.48 X 108.905 = 107.865 amu
2006-11-26 19:09:00 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Multiply each mass by its percentage, add the two answers together, and divide by 100. You're taking a weighted average.
2006-11-26 19:05:53 · answer #3 · answered by TitoBob 7 · 0⤊ 0⤋
do 106.905 x 0.52
and 108.905 x 0.48
then add them together
2006-11-26 19:12:09 · answer #4 · answered by scurvybc 3 · 0⤊ 0⤋
107.8682
2006-11-26 19:08:18 · answer #5 · answered by JJ 7 · 0⤊ 0⤋