English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2 answers

The question doesn't make sense as set. The rules of the game need to be understood. Define "o"; or is this a font limitation? Are f and g to be interpreted as operators, with (f o g)(x) meaning "First find g(x), then find f[g(x)]", etc? Presumably, to avoid possible confusion, you also meant to put not "x.f(x)...etc", but rather "x, where f(x) = ... etc"

If so, then (f o g)(x) = (x^2 + 1)^2 and (g o f)(x) = (x + 1)^4.

Obviously, neither of these successive operations produces merely x; so both answers are a resounding NO!

Live long and prosper.

2006-11-26 11:18:48 · answer #1 · answered by Dr Spock 6 · 0 0

your question does make any sense because exponents will grow up!!!

2006-11-26 10:48:19 · answer #2 · answered by polizei 2 · 0 0

fedest.com, questions and answers