How many positive integers have a value between (square root) of 8 and (square root) of 72?
2006-11-26 09:50:57 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The square root of 8 is just below 3 since this is the square root of 9. The smallest integer required is therefore 3. The square root of 72 is between 8 and 9 since 8 squared is 64 and 9 squared is 81. 8 is therefore the highest value.
There are therefore 6 positive integers...3,4,5,6,7,8
2006-11-26 09:54:44 · answer #1 · answered by helenlouiset 2 · 0⤊ 0⤋
Take the square root (positive) of the given numbers and then identify the integers.
3,4,5,6,7,8
So that's a total of six.
2006-11-26 18:42:06 · answer #2 · answered by Brenmore 5 · 0⤊ 0⤋
If I understand you question you are asking for the positive integers between 2.82 and 8.48.
they would be 3,4,5,6,7,8
2006-11-26 17:57:13 · answer #3 · answered by mom 7 · 0⤊ 0⤋