Just generally.
2006-11-26 09:37:06 · 6 answers · asked by ankit b 1 in Science & Mathematics ➔ Physics
Work out/Work in
2006-11-26 09:39:48 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You have some on-going process that converts energy from one form to another, desired form. For example, your car converts the chemical energy in gasoline to mechanical energy. You find, however, that even though energy (in its broadest sense) is conserved, not all of the energy in the original form winds up in the desired form---only a fraction of it does. This fraction is the efficiency. The energy that does not go into the desired form usually winds up as heat energy somewhere in the system.
2006-11-26 17:44:28 · answer #2 · answered by cosmo 7 · 1⤊ 0⤋
Actual yield/theoretical yield
At least for a chemical reaction that makes sense.
energy in/work out would yield more than 100%
Work out/energy in is what you are thinking I'm guessing.
(In response to an aswer folowing mine)
2006-11-26 18:03:49 · answer #3 · answered by ratbastard39 1 · 1⤊ 0⤋
100% * Energy In / Work Out
2006-11-26 19:39:20 · answer #4 · answered by sojsail 7 · 1⤊ 0⤋
energy lost during whatever work. ex.. cars are very inefficent. much of the gas energy goes to heat
2006-11-26 17:39:12 · answer #5 · answered by Anonymous · 1⤊ 0⤋
if you have to ask, you have failed already
2006-11-26 17:38:34 · answer #6 · answered by Anonymous · 0⤊ 3⤋