Addition and Subtraction Problems?

Question

Write an addition equation and a subtraction equation to model each situation. Use one variable and tell what it represents.

a. Diana has 38 marbles. She and her brother together have 75 marbles.

b. Ramon needs 5 points in the last quarter of the game to tie his high score of 23 points.

c. Spring spent $8 and has $9 remaining.

Answer 1

a. 38 + x = 75 Diana has 38 marbles. Her marbles (38) + her brother's (x) = the amount of marbles they have together (75).

b. 5 + x = 23 Ramon's score has to = 23. He needs 5 more to get to 23.

c. x - 8 = 9 Spring spent 8 from the total amound she started with (x). She now has 9 left.

Answer 2

a.) x+38=75
let x= # of marbles Diana's brother has
75-38=x
let x= # of marbles Diana's borther has

b.) x+5=23
let x= points needed to reach his high score
23-5=x
let x= points needed to reach his high score

c.) x-8=9
let x= money had in all
9+8=x
let x= money had in all






HOPE THIS HELPS!

Answer 3

that's one is greater approximately arranging the equation in a different way. we've 80 4 - x = fifty 8 Shift the 80 4 to the different area, remembering that shifting numbers to different facets ability different indicators as nicely. it is because of the fact: 80 4 - 80 4 - x = fifty 8 - 80 4 (what you do to a minimum of one area, you may do to the different too) the 84s cancel and you get: - x = fifty 8 - 80 4 a reasonable difficulty now.... x is a unfavourable, and it is not an addition difficulty. so which you multiply the completed equation by (-a million) -a million(-x) = (-a million)(fifty 8 - 80 4) Now you get: x = - fifty 8 + 80 4 i think of that is spoke of as an addition difficulty! =)

Answer 4

a) 38 + y =75

b) y + 5 = 23

c) y - 8 = 9

Answer 5

This is not that hard.
a. 38 + x = 75
b. x + 5 = 23

Hopefully, you can do the last one on your own...