A) NH2 CH2 COO-
B) +NH3 CH2 COO-
C) +NH3 CH2 COOH
D) NH2 CH2 COOH
93
2006-11-26 09:09:43 · 7 answers · asked by Michael 1 in Science & Mathematics ➔ Chemistry
Both "ends" would be protonated. Now choose the correct answer!
(It's C)
2006-11-26 09:11:32 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋
In low pH (strongly acidic) species are more protonated due to the excess of H+ ions available so both the carboxyl end and the amino end are protonated. So the answer is C.
(At neutral pH amino acids are in their zwitterionic state, b and at high pH in a deprotonated form, a)
2006-11-27 10:48:19 · answer #2 · answered by Ellie 4 · 0⤊ 0⤋
I think it would be a pear drop
2006-11-26 17:13:34 · answer #3 · answered by Anonymous · 0⤊ 0⤋
do your own homework! cheeky!
2006-11-27 10:48:41 · answer #4 · answered by Curious kitten! 2 · 0⤊ 0⤋
c) as a guess
2006-11-26 17:11:48 · answer #5 · answered by lamyarhull 3 · 0⤊ 0⤋
C
2006-11-30 10:52:12 · answer #6 · answered by luke c 1 · 0⤊ 0⤋
c) +H3NCH2COOH
2006-11-28 16:05:20 · answer #7 · answered by lenpol7 7 · 0⤊ 0⤋