8x³ + 27
2006-11-26 08:23:25 · 5 answers · asked by Sally 1 in Science & Mathematics ➔ Mathematics
(3+2x)(9-6x+4x^2)
2006-11-26 08:25:13 · answer #1 · answered by Michel_le_Logique 4 · 0⤊ 1⤋
8x³ + 27
= (2³)(x³) + (3³) = (2x)³ + (3)³
Notice that everything is "cubed". This is one of the "special cases" of factoring polynomials.
Sum and Difference of Cubes
a³ + b³ = (a + b)(a² -ab + b²)
a³ - b³ = (a - b)(a² + ab + b²)
Our "a" would be 2x, and our "b" would be 3, so:
(2x)³ + (3)³
= (2x + 3)((2x)² - (2x)(3) + (3)²)
= (2x + 3)(4x² - 6x + 9)
2006-11-26 08:40:02 · answer #2 · answered by Anonymous · 1⤊ 0⤋
Hint: If you want to factor x^3 + y^3, a factor is
always x + y. Use this to solve your problem!
2006-11-26 08:46:15 · answer #3 · answered by steiner1745 7 · 0⤊ 1⤋
it is a special equation so
(2x)^3+3^3
(2x+3)(4x^2-6x+9)
2006-11-26 08:28:03 · answer #4 · answered by 7 · 1⤊ 1⤋
im not sure u can cuz they dont have a common factor, u can cube root them but thats about it. if u cube root them u get 2x+3
srry if i wasnt any help
2006-11-26 08:34:57 · answer #5 · answered by Beca <3 4 · 0⤊ 2⤋