Revolve the region bounded by y = 5x and y = x^2 about the y-axis. In cubic units, the resulting volume is?

Question

I got 128pi/3

Answer 1

you need a z variable to compute volumes.

if you mean area, it will not be changed by revolving it, and it will be

integral from 0 to 5 of (5x-x^2)
=(2.5x^2-x^3/3) (x=0:5)
= 2.5*25-125/3 = ...