f(x)= 9/x+7
{x | x is a real number and x is not equal to 9 and x is not equal to -7?
2006-11-26 06:39:58 · 6 answers · asked by crazylifer 3 in Science & Mathematics ➔ Mathematics
This is what always helps me.
A function is a machine.
The domain is everything you can put into the machine so that it doesn't break.
The range is everything you can get out of the machine.
In the case of your function, there's only one possible value of x that will "break" the function, in the sense that you'd get an infinite answer. That value is x=0, because then you'd have 9/0 + 7, and 9/0 is infinity.
So the range is {x | x is not equal to 0}.
Assuming that you meant 9/x + 7, rather than 9/(x+7). If you meant the latter, x cannot be equal to -7.
2006-11-26 06:45:14 · answer #1 · answered by Jim Burnell 6 · 0⤊ 0⤋
{x | x is a real number and x is not equal to -7 }
***x can be 9
2006-11-26 14:43:21 · answer #2 · answered by Patrick 2 · 0⤊ 0⤋
If it is 9/(x+7), x is not equal to -7
If it is (9/x)+7, x is not equal to 0
2006-11-26 14:43:51 · answer #3 · answered by Sora 6 · 0⤊ 0⤋
if y=9 since f(x) means y
9=9/x+7
9-7=9/x+7-7
2=9/x
2/9=x multiply both sides by 1/9
2/9=x
2006-11-26 15:20:58 · answer #4 · answered by sara 2 · 0⤊ 0⤋
x cannot equal zero because 9/0 is undefined.
2006-11-26 14:48:39 · answer #5 · answered by tamana 3 · 0⤊ 0⤋
x can't not be -7
2006-11-26 14:42:22 · answer #6 · answered by 7 · 0⤊ 0⤋