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An Airplane is traveling 25 degrees west of north at 300 m/s when a wind with velocity 100 m/s directed 35 degrees east of north begins to blow.Determine the speed and direction of the resultant velocity.

Please explain to me how to do this with a graph T_T

2006-11-26 06:32:14 · 5 answers · asked by Alex 1 in Science & Mathematics Physics

5 answers

Sorry, it is not a friction question, but a relative velocity question.

If AB is taken as the airplane velocity,BC will be the wind velocity. The angle CAB is (90-25)+(90-35)=65+55=120 degree.
so in the triangle ABC, AB(airplane velocity)=300, BC(wind velocity)=100, angle CAB =120 degree.

AC vector is the resultant velocity. You will get the magnitude simplty by the formula a^2=b^2+c^2+2bccosA, where b=AB, c=BC, A=angle ABC and a= resultant vector or you may get the
result by drawing the figure geometrically.

2006-11-26 07:05:58 · answer #1 · answered by decentguy2006 1 · 0 0

It is a vector sum.

first find the vector equivalent to 25 degrees west of north and the vector 35 degrees east of north.
the north velocity of the plane is 300 sin 65 the west velocity is 300 cos 65 the north velocity of the wind is -100 sin 55 and the west velocity of the wind is 100 cos 55 this will give the components of each that simply get added together.

(300cos 65 +100cos 55) i component +(300sin65 -100sin55)j component.
184m/s i +190m/s j now use these two components to find the new direction and velocity
the direction is arctan190/184 and the magnitude of the vector is the square root of (184^2+190^2)

the direction is 45.919 degrees north of west or 90-45.919 degrees west of north. because i use the x coordinate as the base line and measured the angles from there as it make the calculations a little more straight forward.

the magnitude is 265m/s

so the plane is traveling at 265ms on a heading of 44.081 degrees west of north

Sorry i missed the second part of your question and brads method will give the result. My method just gives the values to draw the vector directly.

2006-11-26 06:50:59 · answer #2 · answered by Anonymous · 0 0

on a piece of coordinate graph paper, draw a set of xy axes. starting at the origin (0,0) and, using a ruler and protractor, draw a line three inches long to a point that is 25 degrees to the left of the vertical axis. next, place your protractor at the upper end of the new line and draw a line one inch long to a point that is 35 degrees to the right of a vertical axis drawn through the end point of the first line. finally, connect the origin with the end of the second line. measure the length of the line and direction from vertical and you have ur answer in m/s and degrees.

2006-11-26 06:50:00 · answer #3 · answered by bardmere 5 · 0 0

I don't think so. What exactly do you mean by down and is getting the friction on safe? I need more info before I commit.

2016-03-29 09:52:14 · answer #4 · answered by Anonymous · 0 0

die whore

2006-11-26 06:41:22 · answer #5 · answered by Jessica T 2 · 0 1

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